inner join

用于根据两个或多个集合中的字段名之间的关系，从这些集合中查询数据。

语法

<collection1_name | (select_set1)> as <alias1_name> inner join <collection2_name | (select_set2)> as <alias2_name> [on condition]

参数

返回值

在集合中存在至少一个匹配时，inner join 返回匹配的记录。

示例

• 集合 foo.persons 中记录如下。

{ "Id_P": 1, "LastName": "Adams", "FirstName": "John", "Address": "Oxford Street", "City": "London" }
{ "Id_P": 2, "LastName": "Bush", "FirstName": "George", "Address": "Fifth Avenue", "City": "New York" }
{ "Id_P": 3, "LastName": "Carter", "FirstName": "Thomas", "Address": "Changan Street", "City": "Beijing" }

• 集合 foo.orders 中记录如下。

{ "Id_O": 1, "OrderNo": 77895, "Id_P": 3 }
{ "Id_O": 2, "OrderNo": 44678, "Id_P": 3 }
{ "Id_O": 3, "OrderNo": 22456, "Id_P": 1 }
{ "Id_O": 4, "OrderNo": 24562, "Id_P": 1 }
{ "Id_O": 5, "OrderNo": 34764, "Id_P": 65 }

• 列出所有人的订购。

> db.exec("select t1.LastName, t1.FirstName, t2.OrderNo from foo.persons as t1 inner join foo.orders as t2 on t1.Id_P=t2.Id_P")
{ "LastName": "Adams", "FirstName": "John", "OrderNo": 22456 }
{ "LastName": "Adams", "FirstName": "John", "OrderNo": 24562 }
{ "LastName": "Carter", "FirstName": "Thomas", "OrderNo": 77895 }
{ "LastName": "Carter", "FirstName": "Thomas", "OrderNo": 44678 }
Return 4 row(s).
Takes 0.43722s.

Note:

• 不能包含非联合条件，如下写法是错误的：

  > db.exec( "select T1.a, T2.b from foo.bar1 as T1 inner join foo.bar2 as T2 on T1.a < 10" ) 

• 不能在 inner join 本层使用 select * 语句。